Calculus — Derivatives6 min read

Quotient Rule

d/dx(f/g) = (gf' − fg') / g²

What is the Quotient Rule?

The quotient rule differentiates a function that's the ratio of two other functions. It's commonly remembered with the mnemonic "low d-high minus high d-low, over low squared" — where "low" is the denominator g and "high" is the numerator f.

The formula requires g(x) ≠ 0 at the point of differentiation, since the original function itself would be undefined there.

What Each Variable Means

f
Numerator functionThe function on top of the fraction ("high").
g
Denominator functionThe function on the bottom ("low") — must not equal zero.
f'
Derivative of the numerator"d-high"
g'
Derivative of the denominator"d-low"

When to Use It

  • Differentiating any expression written as one function divided by another, like x²/(x+1)
  • Deriving tan x's derivative from sin x / cos x
  • Anywhere a rate depends on the ratio of two changing quantities
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Step-by-Step Examples

Example 1: Deriving tan x's derivative

Problem: Differentiate y = sin x / cos x

1
Identify f and g

Split the quotient into numerator and denominator.

f = sin x, g = cos x
2
Find f' and g'

Differentiate each separately.

f' = cos x, g' = -sin x
3
Apply (gf' − fg') / g²

Substitute into the quotient rule.

(cos x · cos x − sin x · (−sin x)) / cos²x
4
Simplify the numerator using cos²x + sin²x = 1

The Pythagorean identity simplifies the top to 1.

= 1 / cos²x
Answer: dy/dx = sec²x — confirming the known derivative of tan x

Example 2: A rational function

Problem: Differentiate y = x² / (x + 1)

1
Identify f and g

Split the quotient into numerator and denominator.

f = x², g = x + 1
2
Find f' and g'

Differentiate each separately.

f' = 2x, g' = 1
3
Apply (gf' − fg') / g²

Substitute into the quotient rule.

((x+1)·2x − x²·1) / (x+1)²
4
Expand and simplify the numerator

Distribute and collect like terms.

(2x² + 2x − x²) / (x+1)² = (x² + 2x) / (x+1)²
Answer: dy/dx = x(x + 2) / (x + 1)²

Common Mistakes

  • Mistake: Reversing the order of subtraction in the numerator.

    Fix: It's gf' − fg' (denominator times numerator's derivative, minus numerator times denominator's derivative) — not the other way around. Getting the order backwards flips the sign of the answer.

  • Mistake: Forgetting to square the denominator.

    Fix: The denominator of the result is g², not just g — a very common dropped exponent.

Practice Questions

  1. Differentiate y = (2x) / (x² + 1).

    Hint: f = 2x, g = x² + 1; f' = 2, g' = 2x.

  2. Differentiate y = (x − 1) / (x + 1).

Frequently Asked Questions

Can the quotient rule be derived from the product rule?

Yes — write f/g as f · g⁻¹, then apply the product rule together with the chain rule (since g⁻¹ is a composite function of g).

What happens if g(x) = 0?

The original function f/g is undefined at that point, so the quotient rule doesn't apply there either — check the domain before differentiating.